The electronic configuration of Gadolinium (G | vedclass

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Question

(C) The atomic number of Gadolinium $(Gd)$ is $64$. Following the Aufbau principle and the stability of half-filled orbitals,the $4f$ subshell is half

Vedclass · Accepted Answer

$[Xe] 4f^7 5d^1 6s^2$

Vedclass · Answer

(C) The atomic number of Gadolinium $(Gd)$ is $64$. Following the Aufbau principle and the stability of half-filled orbitals,the $4f$ subshell is half-filled at Europium ($Eu$,$Z = 63$) with the configuration $[Xe] 4f^7 6s^2$. For the next element,Gadolinium $(Z = 64)$,the $4f$ subshell is already stable (half-filled),so the next electron enters the $5d$ orbital instead of the $4f$ orbital. Therefore,the electronic configuration of $Gd$ is $[Xe] 4f^7 5d^1 6s^2$.

List-$I$ (Transition metal,$M$)	List-$II$ ($E_{M^{2+}/ M}^{\ominus}$ in $V$)
$A$. $Ni$	$I$. $-1.18$
$B$. $Mn$	$II$. $-0.91$
$C$. $Fe$	$III$. $-0.25$
$D$. $Cr$	$IV$. $-0.44$

The electronic configuration of Gadolinium ($Gd$,$Z = 64$) is:

Similar Questions

The basic character of the transition metal monoxides follows the order
(Atomic no. $Ti = 22, V = 23, Cr = 24, Fe = 26$)

An ion which has $18$ electrons in the outermost shell is

Match the following:

List-$I$ (Transition metal,$M$) List-$II$ ($E_{M^{2+}/ M}^{\ominus}$ in $V$)

$A$. $Ni$ $I$. $-1.18$

$B$. $Mn$ $II$. $-0.91$

$C$. $Fe$ $III$. $-0.25$

$D$. $Cr$ $IV$. $-0.44$

The correct answer is

Which of the following ions is colourless in spite of the presence of unpaired electrons?

Calculate the 'spin only' magnetic moment of $M^{2+}_{(aq)}$ ion $(Z=27)$.

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